$ dd bs=2x80x18b if=/dev/fd0 of=/tmp/floppy.image
1+0 records in
1+0 records out
Then to write to another floppy:
$ dd bs=2x80x18b < /tmp/floppy.image > /dev/fd0
1+0 records in
1+0 records out
The 2x multiplies the sector size by the number of heads
while the 80x identifies the number of cylinders. The
18b specifies 18 sectors of 512 bytes. This gives a total of
1,474,560 bytes and issues a single 1,474,560-byte read request to
/dev/fd0 and a single 1,474,560 write request to /tmp/floppy.image,
rather than the corresponding cp command:
$ cp /dev/fd0 /tmp/floppy.image
which issues 360 reads and writes of 4,096 bytes each.
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